{"id":1687,"date":"2025-04-11T12:24:46","date_gmt":"2025-04-11T12:24:46","guid":{"rendered":"https:\/\/webprojects.cloud\/wordpress\/splatco\/?post_type=spl_knowledgebase&p=1687"},"modified":"2025-06-10T07:57:54","modified_gmt":"2025-06-10T07:57:54","slug":"xbio16-connecting-input-devices","status":"publish","type":"spl_knowledgebase","link":"https:\/\/webprojects.cloud\/wordpress\/splatco\/knowledgebase\/product-documentation\/product-documentation-expansion-boards\/xbio16-16-bidirectional-i-os\/xbio16-inputs-and-outputs\/xbio16-i-o-connections\/xbio16-connecting-input-devices\/","title":{"rendered":"XBIO16: Connecting input devices"},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n

The adjacent picture shows the two I\/O connectors and two typical input devices.<\/p>\n\n\n\n

Each connector contains the connections for 8 I\/Os. It also has a positive supply connection labeled + and a common return labeled 0V.<\/p>\n\n\n\n

In the picture A is the output of an NPN style sensor connected to I\/O 10. B is a simple switch connected to I\/O 4. The sensor would also require a positive supply voltage to power it. See the manufacturer’s data for connection details of the sensor you are using. The terminal labeled with a minus sign above will be the manufacturer’s designated negative or common terminal, and the “O” terminal will be the designated output terminal of the sensor.<\/p>\n\n\n\n

The input is ON when the input pin is connected to 0V (Gnd). Under that condition a (positive) current flows out of the input pin, through the external circuit, to 0V. The magnitude of that current depends on the supply voltage. Assuming a dead short between the input pin and 0V, the current is given by the equation<\/p>\n\n\n\n

I(in) = – (V(supply) – 1.6V) \/ 4700<\/p>\n\n\n\n

The leading minus sign simply means the current is flowing out<\/em> of the pin. The 1.6V represents the voltage drop of the input indicator LED. The 4700 represents the input pullup resistance.<\/p>\n\n\n\n

This equation translates to about 2.2mA with a 12V supply and 4.8mA with a 24V supply. This is low enough to be compatible with all off-the-shelf NPN style sensors. The inputs are not compatible with PNP style sensors.<\/p>\n\n\n\n

Take care when driving the inputs from switch or relay contacts. The problem is “contact wetting” (or a lack of it) and due not to too much current but to too little current. You should select contacts that are designed for low level switching. There is an article about this\u00a0here<\/a>.<\/p>\n\n\n\n

You should also be aware that the board will only recognize the input as ON when the voltage on the input pin is typically<\/em> less than 6V. That means the input needs to be a “fairly solid” connection to 0V.<\/p>\n\n\n\n

A word of caution: In practice the threshold voltage of the input is related to the threshold of the input chip, which has fairly wide uncertainty. Due to this uncertainty the input can only be guaranteed to be ON if it is less than 3V, and can only be guaranteed to be seen as OFF if it is over 9V. The range between 3V and 9V is a “no man’s land” where behaviour is not guaranteed. That means that you may determine experimentally that something works OK on a prototype, but that gives you no right to assume it will therefore work on all future units.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
How to blow up a bidirectional I\/O circuit<\/h6>\n\n\n\n

You can blow up the I\/O circuits by:<\/p>\n\n\n\n

    \n
  1. Exceeding output current or voltage ratings.<\/li>\n\n\n\n
  2. Connecting the I\/O pin directly to the positive supply voltage (or to any other voltage source capably of delivering more than 4-500 mA) and turning (programming) the output ON<\/li>\n\n\n\n
  3. Connecting the output pin to any negative voltage.<\/li>\n\n\n\n
  4. Connecting the output pin to any voltage greater than the positive supply.<\/li>\n\n\n\n
  5. Switching an output load that has a large amount of capacitance, i.e. draws large surge current. This could be the case if you tried using an output to activate some other piece of equipment by switching its DC power on and off.<\/li>\n\n\n\n
  6. Driving (output) an AC solenoid or relay coil in place of a DC coil. An AC coil will typically draw 10 to 15 times its rated current if accidentally used in a DC circuit.<\/li>\n\n\n\n
  7. Driving (output) an incandescent lamp load rated at more than 10% of the output’s peak output rating. Incandescent lamps draw a warm-up surge current of many (up to 15) times their rated steady state current.<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

    The adjacent picture shows the two I\/O connectors and two typical input devices. Each connector contains the connections for 8 I\/Os. It also has a…<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1686,"menu_order":0,"template":"","class_list":["post-1687","spl_knowledgebase","type-spl_knowledgebase","status-publish","hentry"],"acf":[],"yoast_head":"\nXBIO16: Connecting input devices - SPLat Controls<\/title>\n<meta name=\"robots\" content=\"noindex, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"XBIO16: Connecting input devices - SPLat Controls\" \/>\n<meta property=\"og:description\" content=\"The adjacent picture shows the two I\/O connectors and two typical input devices. Each connector contains the connections for 8 I\/Os. 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